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Question

If x=n=0(1)ntan2nθ and y=n=0cos2nθ, where 0<θ<π4, then:

A
y(1+x)=1
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B
x(1y)=1
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C
y(1x)=1
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D
x(1+y)=1
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Solution

The correct option is C y(1x)=1
y=1+cos2θ+cos4θ+
y=11cos2θ1y=sin2θ
x=1tan2θ+tan4θ
x=11(tan2θ)=cos2θ
x+1y=1y(1x)=1

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