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Question

If x=n=0an,y=n=0bn,z=n=0cn where a, b, c are in AP and |a|<1,|b|<1,|c|<1 then x, y, z are in:
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Solution

All three are sum of infinite G.P. with
r ( multiply ratio) <1{|a|,|b|,|c|<1}
Sum of infinite G.P. n=0an=11a
Sum of infinite G.P. bn=11b,cn=11c
1x=1a,1y=1b,1z=1c
1y1x=ab,1z1y=bc
As a,b,c are in A.P,ab and bc are equal
1x,1y,1z are in A.P.
x,y,z are in H.P.

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