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Question

If x=n=0an,y=n=0bn,z=n=0cn where a,b,c are in A.P. and |a|<1,|b|<1,|c|<1

A
GP
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B
AP
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C
Arithmetic-Geometric Progression
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D
HP
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Solution

The correct option is D HP
Consider the given expression.
x=n=0an

x=1+a+a2+a3+.....+

x=11a

a=x1x ......... (1)

Similarly,
b=y1y ......... (2)

c=z1z ......... (3)

Since, a,b,c are in A.P,

Therefore,
2b=a+c

2×y1y=x1x+z1z

(2y2)(xz)=xyzzy+xyzxy

2xyz2xz=2xyzxyzy

2xz=y(x+z)

y=2xzx+z

Therefore, x,y,z are in H.P.

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