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Question

If x=n=0an,y=n=0bn,z=n=0cn, where a , b , c are in A . P . such that |a |<1, |b| > <1 and |c| < 1 then show that x , y , z are in H . P

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Solution

x=11aa=11xbySum of infinity terms for G . P.
Similarly b,c are b=11y,c=11z
a , b , c are in A . P . 2b = a + c
2(11y)=a1x+a1z2y=1x+1z1x,1y,1z are in the A . P . or x , y , z , are in H . P

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