If x=∑∞n=0an,y=∑∞n=0bn,z=∑∞n=0cn, where a , b , c are in A . P . such that |a |<1, |b| > <1 and |c| < 1 then show that x , y , z are in H . P
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Solution
x=11−a⇒a=1−1xbySum of infinity terms for G . P.
Similarly b,c are b=1−1y,c=1−1z ∵ a , b , c are in A . P . ⇒ 2b = a + c ∴2(1−1y)=a−1x+a−1z⇒2y=1x+1z⇒1x,1y,1z are in the A . P . or x , y , z , are in H . P