If x(t) be a signal with Nyquist rate 100 Hz. The Nyquist rate for the signal $x (t) c o s 100 π t$ is ___Hz.

200

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Solution

The correct option is A 200
Nyquist rate of x(t) is 100 Hz

$2 f_{m} = 100, f_{m} = 50$

Maximum frequency present in x(t) is 50 Hz.

$∴$ Maximum frequency of the signal $x (t) c o s (100 π t)$ is $50 + 50 = 100 H z .$

$∴$ Nyquist rate for the signal $x (t) c o s (100 π t)$ is $2 \times 100 = 200 H z .$

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