If x(t) = u(sin t), then Fourier series of x(t) will contain

dc and odd harmonics of sine terms

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all harmonics of sine terms will be zero dc

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dc and all harmonics of sine terms

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only odd harmonics of sine terms

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Solution

The correct option is A dc and odd harmonics of sine terms
(b)

X(t ) = u(t)
Drawing waveform of sin t and x(t)

y(t) has zero dc component

y(t) = sine terms with odd harmonics
performing upward shift in y(t) by adding dc value of 0.5
x(t) = y(t) + 0.5
So, x(t) has dc and sine terms with odd harmonics.

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