If x - tan e - y - show that d y - d x - - e y - 1 - x 2

x=tan( e ^ y ) tan ^ 1 (x)= e ^ y #160;Now on differentiation, we get; 1 1+ x ^ 2 = e ^ y dy dx dy dx = e ^ y 1+ x ^ 2 (An ...

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If x = tan ...

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If $x = tan (e^{- y}),$ show that $\frac{d y}{d x} = \frac{- e^{y}}{1 + x^{2}}$

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