If $x \times t a n (45^{\circ}) \times c o s (60^{\circ}) = sin (60^{\circ}) \times c o t (60^{\circ})$ , then $x =$

1

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\frac{1}{2}

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\frac{1}{\sqrt{2}}

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\sqrt{3}

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Solution

The correct option is A $1$
$x = \frac{sin 60^{\circ} cot 60^{\circ}}{cos 60^{\circ} tan 45^{\circ}} = \frac{tan 60^{\circ} cot 60^{\circ}}{tan 45^{\circ}}$

$x = \frac{\sqrt{3} . \frac{1}{\sqrt{3}}}{1} = 1$

Suggest Corrections

Similar questions

$s i n 60^{\circ} c o s 45^{\circ} t a n 45^{\circ} c o t 60^{\circ} s e c 30^{\circ} c o s e c 90^{\circ}$

\frac{1}{2}

\frac{1}{\sqrt{2}}

\sqrt{3}

sin 60^{\circ} cos 45^{\circ} + cos 60^{\circ} sin 45^{\circ} = \frac{\sqrt{3 + 1}}{2 \sqrt{2}}

\frac{c o s 30^{\circ} + s i n 60^{\circ}}{1 + c o s 60^{\circ} + s i n 30^{\circ}} = \frac{\sqrt{3}}{2}

Show that:

(i) $\frac{1 - sin 60^{\circ}}{cos 60^{\circ}} = \frac{tan 60^{\circ} - 1}{tan 60^{\circ} + 1}$

(ii) $\frac{cos 30^{\circ} + sin 60^{\circ}}{1 + sin 30^{\circ} + cos 60^{\circ}} = cos 30^{\circ}$

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