If x, v and a represent the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T then which of the following does not change ?
A
aTv
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B
aT+2πv
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C
aTx
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D
a2T2+2π2v2
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Solution
The correct option is CaTx Given:
Displacement= x
Velocity=V
Acceleration=a
For SHM partical,
a=ω2x ...........(1)
ω=2πT
On putiong the value of ω in equation (1)
a=(2πT)2x
4π2=aT2x
4πT=aTx........(2)
From equation (2) LHS is constant hence RHS will be constant.