Question

Question 56

If x varies inversely as y and when x = 6, y = 8, then x = 8, the value of y is 10.

Answer 1

False
if x varies inversely as y. i.e. xy = k (constant)
If x = 6 and y = 8
$\therefore xy=6\times 8=48$
But if x = 8 and y = 10
$\therefore xy=8\times 10=80$
Here, $48\ne 80$
Hence, the value of y is not 10.