If $x (x - 5) = 6$ , then $x = 6, - 1$
If true then enter $1$ and if false then enter $0$ .

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Solution

Given equation is $x (x - 5) = 6$
$∴ x^{2} - 5 x - 6 = 0$
$x^{2} - 6 x + x - 6 = 0$
$(x - 6) (x + 1) = 0$
$∴ x = - 1, 6$

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