If $x + y > 0$ when $x > y$ , which of the following cannot be true?

x = -4 and y = -3

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x = -3 and y = 0

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x = 6 and y = -1

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x = 3 and y = 0

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x = 3 and y = -3

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Solution

The correct option is E x = 3 and y = -3
Given $x + y > 0$ when $x > y$
Consider option $E$ , given that $x = 3$ and $y = - 3$
Here $x > y$ but $x + y = 0$ (given $x + y > 0$ )
So the correct option is $E$

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If x+y>0 when x>y, which of the following cannot be true?

The correct option is E x = 3 and y = -3Given x+y>0 when x>yConsider option E , given that x=3 and y=−3Here x>y but x+y=0 (given x+y>0)So the correct option is E

If $x + y > 0$ when $x > y$ , which of the following cannot be true?

The correct option is E x = 3 and y = -3
Given $x + y > 0$ when $x > y$
Consider option $E$ , given that $x = 3$ and $y = - 3$
Here $x > y$ but $x + y = 0$ (given $x + y > 0$ )
So the correct option is $E$