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Theorem 1: Equal Chords Subtend Equal Angles at the Center

If x+y-1x-1+y...

Question

If (x+y)^-1(x^-1+y^-1)= x^p y^q, then p+q is equal to

A

2

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B

-1

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C

-2

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D

1

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Solution

The correct option is C
-2

(x+y)-1(x-1+y-1)=xp yq

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Similar questions

x^{p} y^{q} = (x + y)^{p + q}

then prove that

\frac{d y}{d x} = \frac{y}{x}

y = {sec}^{- 1} (\frac{x + 1}{x - 1}) + {sin}^{- 1} (\frac{x - 1}{x + 1})

\frac{d y}{d x}

x = \frac{y}{(1 + p)^{q}}

q

x^{p} y^{q} = (x + y)^{p + q}

\frac{d y}{d x}

x = \frac{y}{(1 + p)^{q}}

, then q is equal to

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Theorem 1: Equal Chords Subtend Equal Angles at the Center

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