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Question

If x+y=12 and xy=32, find the value of x2+y2.


A

80

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B

90

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C

100

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D

110

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Solution

The correct option is A 80


Since (x+y)2=x2+y2+2xy

144=x2+y2+2×32 [Substituting x + y = 12 and xy = 32]

14464=x2+y2

x2+y2=80

Hence, x2+y2=80


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