If x+y=12 and xy=32, find the value of x2+y2.
80
90
100
110
The correct option is A 80
Since (x+y)2=x2+y2+2xy
144=x2+y2+2×32 [Substituting x + y = 12 and xy = 32]
144–64=x2+y2
x2+y2=80
Hence, x2+y2=80
If x + y = 12 and xy = 32, find x2 + y2.