If $x + y = 3$ and $3 x - 2 y - 4 = 0$ find $x, y$

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Solution

Given equations:

$x + y = 3$ ....(1)

$3 x - 2 y - 4 = 0 \Rightarrow 3 x - 2 y = 4$ ....(2)

$3 \times (1) - (2)$ gives,

$5 y = 5$

$\Rightarrow y = 1$

putting the value of y in equation (1), we get,

$x = 3 - y = 3 - 1 = 2$

$∴ x = 2, y = 1$

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