If (x+y)3−(x−y)3−6y(x2−y2) = ky2 , then k =
1
2
4
8
(x+y)3−(x−y)3−6y(x2−y2)=ky2LHS=(x+y)3−(x−y)3−3times(x+y)(x−y)[x+y−x+y]=(x+y−x+y)3=(2y)3=8y3
Hence k = 8
Prove that (x+y)3 - (x-y)3 - 6y(x2 - y2 ) = 8y3