If x-y-4-0- then find the value of x3-b3-12 x y-64

Given (x + y + 4) = 0 ⇒ x + y = –4 → (1) Cubing on both the sides, we get (x + y)3 = –43 ⇒ x3 + y3 + 3xy(x + y) = –64 ⇒ x3 + y3 + 3xy(–4 ) = –64 [From equati ...

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Standard IX

Mathematics

Linear Equation in Two Variables

if x+y+4=0, t...

Question

if x +y+ 4 =0 , then find the value of x³ + b³- 12xy + 64

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Solution

Given (x + y + 4) = 0
⇒ x + y = –4 → (1)
Cubing on both the sides, we get
(x + y)³ = –4³
⇒ x³ + y³ + 3xy(x + y) = –64
⇒ x³ + y³ + 3xy(–4 ) = –64 [From equation (1)]
⇒ x³ + y³ –12xy + 64 = 0

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if x +y+ 4 =0 , then find the value of x3 + b3 - 12xy + 64

Given (x + y + 4) = 0 ⇒ x + y = –4 → (1) Cubing on both the sides, we get (x + y)3 = –43 ⇒ x3 + y3 + 3xy(x + y) = –64 ⇒ x3 + y3 + 3xy(–4 ) = –64 [From equation (1)] ⇒ x3 + y3 –12xy + 64 = 0

if x +y+ 4 =0 , then find the value of x³ + b³- 12xy + 64

Given (x + y + 4) = 0
⇒ x + y = –4 → (1)
Cubing on both the sides, we get
(x + y)³ = –4³
⇒ x³ + y³ + 3xy(x + y) = –64
⇒ x³ + y³ + 3xy(–4 ) = –64 [From equation (1)]
⇒ x³ + y³ –12xy + 64 = 0