If x- y-4- 3- then x y-y2-x2-y2 will be equal to-

The correct option is B 3Let x = 4k and y = 3k xy + y^2 = 3k × 4k + (3k)^2 = 21k^2 x^2 y^2 = (4k)^2 (3k)^2 = 7k^2 xy+y^2/x^2 y^2 = 21k^2/7k^2 = 3 nbs ...

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Standard X

Mathematics

Quadratic Formula

If x: y=4: 3,...

Question

If x: y = 4: 3, then $\frac{x y + y^{2}}{x^{2} - y^{2}}$ will be equal to:

0.84

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2.1

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None of the above

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Solution

The correct option is B 3
Let x = 4k and y = 3k

xy + y $^{2}$ = 3k $\times$ 4k + (3k) $^{2}$ = 21k $^{2}$

x $^{2}$ - y $^{2}$ = (4k) $^{2}$ - (3k) $^{2}$ = 7k $^{2}$

$\frac{x y + y^{2}}{x^{2} - y^{2}}$ = $\frac{21 k^{2}}{7 k^{2}} = 3$

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If x: y = 4: 3, then xy+y2x2−y2 will be equal to:

The correct option is B 3Let x = 4k and y = 3k xy + y2 = 3k × 4k + (3k)2 = 21k2 x2 - y2 = (4k)2 - (3k)2 = 7k2 xy+y2x2−y2 = 21k27k2=3

If x: y = 4: 3, then $\frac{x y + y^{2}}{x^{2} - y^{2}}$ will be equal to:

The correct option is B 3
Let x = 4k and y = 3k

xy + y $^{2}$ = 3k $\times$ 4k + (3k) $^{2}$ = 21k $^{2}$

x $^{2}$ - y $^{2}$ = (4k) $^{2}$ - (3k) $^{2}$ = 7k $^{2}$

$\frac{x y + y^{2}}{x^{2} - y^{2}}$ = $\frac{21 k^{2}}{7 k^{2}} = 3$