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Byju's Answer
Standard XII
Physics
The Problem of Areas
If x+y=5 an...
Question
If
x
+
y
=
5
and
x
2
+
y
2
=
111
, then value of
x
3
+
y
3
is:
A
770
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B
227
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C
555
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D
115
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Solution
The correct option is
B
770
Given,
x
+
y
=
5
,
x
2
+
y
2
=
111
We know
x
2
+
y
2
=
(
x
+
y
)
2
−
2
x
y
⇒
111
=
(
5
)
2
−
2
x
y
⇒
2
x
y
=
25
−
111
=
−
86
⇒
x
y
=
−
43
Therefore,
x
3
+
y
3
=
(
x
+
y
)
(
x
2
−
x
y
+
y
2
)
=
(
5
)
(
111
+
43
)
=
154
×
5
=
770
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2
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