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Question

If x+y=5 and x2+y2=111, then value of x3+y3 is:

A
770
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B
227
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C
555
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D
115
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Solution

The correct option is B 770
Given, x+y=5,x2+y2=111
We know x2+y2=(x+y)22xy
111=(5)22xy2xy=25111=86xy=43
Therefore, x3+y3=(x+y)(x2xy+y2)
=(5)(111+43)=154×5
=770

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