If $x + y = 7, x y = 0$ , then find $x^{3} + y^{3}$ .

131

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133

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343

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- 131

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Solution

The correct option is C $343$
Given: $x + y = 7$
Cubing both sides, we get
$(x + y)^{3} = 7^{3}$
or $x^{3} + y^{3} + 3 x y (x + y) = 343$ {Using standard cubic identity}
or $x^{3} + y^{3} + 3 \times 0 \times 7 = 343$ { $∵ x y = 0$ }
or $x^{3} + y^{3} = 343$

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