If x y - a x - prove that d y d x -log alog x-1log x2-

x^y=a^x⇒ y log x= x log a y=x/log xlog a dy/dx= log a {log x x.1/x/(log x)^2}= log a{log x 1/(log x)^2} ...

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Property 4

If x y = a...

Question

If $x^{y} = a^{x},$ prove that $\frac{d y}{d x} = \frac{log a (log x - 1)}{(log x)^{2}}$ .

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