If x ∝ y , and y = 9 when x = 3. If value of y = 27 then value of x =
6
9
12
15
If x ∝ y then x varies directly as y.
When y = 9 , x = 3
Putting this in x = ky we get 3 = 9k
⇒ k =1/3
putting k = 1/3 and y = 27 in x = ky we get x = 27/3 = 9.
Find the value of x3+27y3+9x2y+27xy2 when x=55 and y=15.
Find the value of 27x3+8y3, if
(i) 3x + 2y = 14 and xy = 8
(ii) 3x + 2y = 20 and xy = 149