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Question

If x,y and z are in AP, then x, y-1 and z are in?

A
AP
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B
GP
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C
HP
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D
a or b
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E
none of these
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Solution

The correct option is C HP

Option (c) Take y=2 and = 1 and (y+z)/(1-yz) = 3

When y=2. x= -1/3 and z= 1/7,

= 1/2 = y-1 .. hence they are in HP


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