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Question

If x,y are positive and x3y2=6. The least value of is 4x+3y is

A
\N
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B
5
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C
10
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D
50
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Solution

The correct option is C 10

x,y positive with x3y2=6 we can use AM-GM inequality by suitable choice of corfficients
4x+3y=3(43)x+2(32y)=(43x+43x+43x+32y+32y)
5((43x)3(32y)2)15
=5(6427×94)15(x3y2)15
=5(1636)15=52=10
the least value is 10


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