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Static Friction

If x ,y are p...

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{ If }x ,y are positive real numbers satisfying the }}{ system of equations }x^2+y\sqrt{xy}=336}{y^2+x\sqrt{xy}=112, then }x+y equals

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x \neq y

x, y

are real numbers; and

A = x^{2} + y^{2} - x y - x - y + 1

Q. Given that both

x

y

are positive integers. Solve the following systems of equations.

x^{2} + x y = 15, y^{2} + x y = 10

{log}_{10} (x^{3} + y^{3}) - {log}_{10} (x^{2} + y^{2} - x y) \leq 2

where x, y are positive real numbers Then the maximum value of

x y

{log}_{10} (x^{3} + y^{3}) - {log}_{10} (x^{2} + y^{2} - x y) \leq 2

x

y

are positive real numbers. Then the maximum value of

^{'} x y^{'}

x^{y} = y^{x}

x^{2} = y,

x

y

are distinct Positive real number, then the value of

x + 2 y

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