wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x,yR, satisfy the equation x2+y24x2y+5=0, then the value of the expression (xy)2+4xyx+xy, is

A
2+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2+12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
212
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2+12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2+12
Given equation is
x2+y24x2y+5=0(x2)2+(y1)2=0
x=2,y=1 ...(1)

Now,
((xy)2+4xy)(x+xy)=(x+y)2(x+xy)=(x+y)2x(x+y)=(x+y)x

Substituting values from (1) , we get
((xy)2+4xy)(x+xy)=(2+1)2=(2+1)2
Hence, option 'D' is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon