Question

If $x,y\text{and}z$ are electronegativity, ionisation potential and electron-affinity respectively. Then the electron affinity $\left(z\right)$ in the terms of electronegativity $\left(x\right)$ and ionisation potential $\left(y\right)$ will be:

• A. $z=\frac{x+y}{z}$
• B. $z=\frac{x-y}{z}$
• C. $z=\frac{x^2-y^2}{z}$
• D. $z=2x-y$

Answer 1

The correct option is D $z=2x-y$

As we know,
$EN=\frac{I.E+E.A}{2}$
$E.A=2E.N-I.E$
$E.N=X$
$I.E=Y$
$E.A=Z$
$\therefore Z=2X-Y$