If x - yxyx-then dy-dx at x - 1 is

X = nbsp;y^x^y^x.......∞⇒ x = y^x^x ⇒ ln x = x^x ln y nbsp; Differentiating nbsp; on both sides nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbs ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Logarithmic Differentiation

If x = yxyx.....

Question

If $x = y^{x^{y^{x} . . . . . . . \infty}} then \frac{d y}{d x} at x = 1$ is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x = y^{x^{y^{x} . . . . . . . \infty}} then \frac{d y}{d x} at x = 1

y = \sqrt{x} + \frac{1}{\sqrt{x}},

\frac{d y}{d x}

x = 1

y^{x} - x^{y} = 1

\frac{d y}{d x}

x = 1

\sqrt{x} + \sqrt{y} = 4

\frac{d y}{d x}

x = 1

y = (1 - x) (1 + x^{2}) (1 + x^{4})

\frac{d y}{d x}

Join BYJU'S Learning Program