wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If xy.yx=16,then dydx at (2,2) is

A
- 1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A - 1
xy.yx=16
logexy+loge yx=loge 16
y loge x+x loge y=4 loge 2
Now, differentiating both sides w.r.t.x
yx+loge x dydx+xydydx+loge y.1=0
dydx=(loge y+yx)(loge x+xy)
dydx|(2,2)=(loge 2+1)(loge 2+1)=1

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Logarithmic Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon