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Question

If x+y+z=0
then x3+y3+z3 =___?


A

0

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B

-3xyz

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C

3xyz

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D

2xyz

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Solution

The correct option is C

3xyz


We know that, x3+y3+z33xyz = (x+y+z)(x2+y2+z22xy2yz2zx)

If x+y+z=0 then,
x3+y3+z33xyz=(0)(y2+z22xy2yz2zx)=0

x3+y3+z3=3xyz


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