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Question

If x+y+z=6 and z is an odd digit, then the three-digit number xyz is


A

an odd multiple of 3

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B

odd multiple of 6

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C

even multiple of 3

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D

even multiple of 9

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Solution

The correct option is A

an odd multiple of 3


Explanation of the correct option

It is given that x+y+z=6 and z is an odd digit.

The number xyz is divisible by 3 as the sum of the digits is divisible by 3.

z is an odd digit. and clearly z is less than 6, so z is either 1 or 3as it can not be 5

The last digit is odd so the number is not even.

Hence Option A is correct


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