Question

If $x+y+z=6$ and $z$ is an odd digit, then the three-digit number $xyz$ is

• A. an odd multiple of $3$
• B. odd multiple of $6$
• C. even multiple of $3$
• D. even multiple of $9$

Answer 1

The correct option is A

an odd multiple of $3$

Explanation of the correct option

It is given that $x+y+z=6$ and $z$ is an odd digit.

The number $xyz$ is divisible by $3$ as the sum of the digits is divisible by $3$.

$z$ is an odd digit. and clearly $z$ is less than $6$, so $z$ is either $1$ or $3$as it can not be $5$

The last digit is odd so the number is not even.

Hence Option $\left(\mathrm{A}\right)$ is correct