Question

If $x+y+z=6$ and $z$ is an odd digit, then the three-digit number $xyz$ is

• A. An odd multiple of $3$
• B. Odd multiple of $6$
• C. Even multiple of $3$
• D. Even multiple of $9$

Answer 1

The correct option is A An odd multiple of $3$

Given, $x+y+z=6$

$\Rightarrow$ The number $xyz$ is divisible by $3$ as the sum of digits is divisible by $3$

Also, the last digit of the number i.e., $z$, is odd.

$\Rightarrow$The number is not divisible by $2$

Hence, $xyz$ is an odd multiplied of $3$.

And option (A) is correct.