wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x, y, z are different from zero and 1+x1111+y1111+z=0, then the value of x−1 + y1 + z1 is

(a) xyz
(b) x−1 y1 z1
(c) − x − y − z
(d) − 1

Open in App
Solution

1+x1111+y1111+z=0x0-z0y-z111+z=0 Applying R2R2-R3 and R1R1-R3xy1+z+z+1yz=0 Expanding along first columnxy+yz+z+yz=0xy+xyz+xz+yz=0xy+yz+zx=-xyzxyxyz+yzxyz+zxxyz=-xyzxyz1z+1x+1y=-1x-1+y-1+z-1=-1

Hence, the correct option is (d).

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Componendo and Dividendo
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon