If x, y, z are in H.P., then the value of expression log(x + z) + log(x - 2y + z) will be
2log(x - z)
If x, y, z are in H.P., then y = 2xzx+z
Now, loge(x+z)+loge(x−2y+z)
= loge{(x+z)(x−2y+z)}
= loge[(x+z)(x+z−4xzx+z)]
= loge[(x+z)2−4xz] = loge(x−z)2 = 2loge(x−z)