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Concept of Inequality

If x, y, z ar...

Question

If x, y, z are next three consecutive integers in the pattern 10, 7, 4, 1, ._ _, _ _, _ _, then (x –1) equals

यदि x, y, z, प्रारूप 10, 7, 4, 1, ._ _, _ _, _ _, के अगले तीन क्रमागत पूर्णांक है, तब (x –1) का मान है

z – y

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y – z

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y + z

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Solution

The correct option is A z – y
Answer (a)

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A = ⎡ ⎢ ⎣ \begin{matrix} x & 3 & 7 4 & x - 1 & 7 4 & 1 & x + 5 \end{matrix} ⎤ ⎥ ⎦,

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If a+b = $α$ ,ab = $β$ ,and a, $H_{1}$ , $H_{2}$ ,b form H.P,then $\frac{1}{H_{1}}$ + $\frac{1}{H_{2}}$ equals to

h_{1}, h_{2}, h_{3}

\frac{1}{h_{1}} + \frac{1}{h_{2}} + \frac{1}{h_{3}}

\frac{a}{R}

H_{1}, H_{2}, . . . . . . ., H_{n}, b

\frac{1}{a}, \frac{1}{H_{1}}, \frac{1}{H_{2}}, . . . . . . . . . ., \frac{1}{H_{n}}, \frac{1}{b}

\frac{a - b}{(n + 1) a b}

M {B r}_{2}

(0.05 M)

H_{2} S

p H

M S

X

K_{s p}

M S = 6.0 \times 10^{- 21}

H_{2} S = 0.1 M

K_{1} = 10^{- 7}

K_{2} = 1.3 \times 10^{- 13}

H_{2} S

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