If x, y, z are positive numbers such that x + [y] + {z} = 3.8, [x] + {y} + z = 3.2, {x} + y + [z] = 2.2, where [p] denotes the greatest integer less than or equal to p and {p} denotes the fractional part of p. E.g. [1.23] = 1, {1.23} = 0.23 = 23100. The numerical value of [x2+y2+z2] is -
9
Adding the three equations we get, 2(x+y+z)=9.2⟹x+y+z=4.6.
Subtracting first eq. from the above eq. we get {y}+[z]=0.8⟹{y}=0.8 and [z]=0.
Subtracting second eq. from the above eq. {x}+[y]=1.4⟹{x}=0.4 and [y]=1.
Subtracting third eq. from the above eq. [x]+{z}=2.4⟹[x]=2 and {z}=0.4.
∴x=2.4,y=1.8 and z=0.4.
Hence, choice (c) is the right answer.