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Question

If x,y,z are positive real numbers and a,b,c are rational numbers, then the value of 11+xba+xca+11+xab+xcb+11+xbc+xac is

A
1
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B
0
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C
1
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D
None of these
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Solution

The correct option is C 1
11+xba+xca+11+xab+xcb+11+xac+xbc

=11+xbxa+xcxa+11+xaxb+xcxb+11+xaxc+xbxc

=xaxa+xb+xc+xbxa+xb+xc+xcxa+xb+xc

xa+xb+xcxa+xb+xc=1

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