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Byju's Answer
Standard IX
Mathematics
Polynomial and Its General Form
If x, y, z ar...
Question
If x, y, z are positive real numbers, show that
√
x
−
1
y
×
√
y
−
1
z
×
√
z
−
1
x
=
1
.
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Solution
√
x
−
1
y
×
√
y
−
1
z
×
√
z
−
1
x
=
√
y
x
×
√
z
y
×
√
x
z
[
∵
a
−
1
=
1
a
]
=
√
y
√
x
×
√
z
√
y
×
√
x
√
z
=
1
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1
Similar questions
Q.
Show that
√
x
−
1
y
.
√
y
−
1
z
.
√
z
−
1
x
=
1
Q.
The value of
x
+
y
+
z
x
−
1
y
−
1
+
y
−
1
z
−
1
+
z
−
1
x
−
1
Q.
√
x
−
1
y
.
√
y
−
1
z
.
√
z
−
1
x
=
Q.
If
x
,
y
,
z
∈
[
−
1
,
1
]
such that
cos
−
1
x
+
cos
−
1
y
+
cos
−
1
z
=
0
, find
x
+
y
+
z
.
Q.
If x, y, z are natural numbers such that
c
o
t
−
1
x
+
c
o
t
−
1
y
=
c
o
t
−
1
z
then the number of ordered triplets (x,y,z) that satisfy the equation is ___
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