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Question

If x,y,z are real numbers satisfying the equations x+[y]+{z}=12.00,[x]+{y}+z=13.54,{x}+y+[z]=14.70, where [.] & {.} represents greatest integer function & fractional part respectively,
then

A
x+y+z=20.12
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B
(x+z) is an integer
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C
[y]+{x}+{z}=7
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D
([x]+[y]+[z]) is an odd integer.
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Solution

The correct options are
A x+y+z=20.12
B (x+z) is an integer
C [y]+{x}+{z}=7
D ([x]+[y]+[z]) is an odd integer.
2013393_293031_ans_727ba668357044999b2b3ab147b7709c.jpg

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