If x,y,z are real numbers satisfying the equations x+[y]+{z}=12.00,[x]+{y}+z=13.54,{x}+y+[z]=14.70, where [.] & {.} represents greatest integer function & fractional part respectively, then
A
x+y+z=20.12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(x+z) is an integer
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
[y]+{x}+{z}=7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
([x]+[y]+[z]) is an odd integer.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are Ax+y+z=20.12 B(x+z) is an integer C[y]+{x}+{z}=7 D([x]+[y]+[z]) is an odd integer.