Question

If $x,y,z$ are real numbers such that $\sqrt{x-1}+\sqrt{y-2}+\sqrt{z-3}=0$ then the values of $x,y,z$ are respectively

• A. $1,2,3$
• B. $0,0,0$
• C. $2,3,1$
• D. $2,4,1$

Answer 1

The correct option is A $1,2,3$

$\sqrt{x-1}+\sqrt{y-2}+\sqrt{z-3}=0$
$\sqrt{x-1}=0$
$\Rightarrow x-1=0$
$\Rightarrow x=1$
$\sqrt{y-2}=0$
$\Rightarrow y-2=0$
$\Rightarrow y=2$
$\sqrt{z-3}=0$
$\Rightarrow z-3=0$
$\Rightarrow z=3$
$Hence(x,y,z)=(1,2,3)$