If x, y, z be rational numbers such that x > y and z < y then ..........

z > x

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z < x

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y < z

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y > x

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Solution

The correct option is B z < x
x > y and y > z
$∴$ x > y > z
$⟹$ x > z

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Similar questions

\frac{x (y + z - x)}{log x} = \frac{y (z + x - y)}{log y} = \frac{z (z + x - y)}{log z},

x^{y} y^{x} = z^{y} y^{z} = x^{z} z^{x}

A = ⎡ ⎢ ⎣ \begin{matrix} x & y & z y & z & x z & x & y \end{matrix} ⎤ ⎥ ⎦

x, y

z

x + y + z > 0

x y z = 2

A^{2} = I_{3}

x^{3} + y^{3} + z^{3}

x^{2} + x y + x z = 135, y^{2} + y z + x y = 351

z^{2} + z x + z y = 243

(x, y, z > 0)

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