If x + y + z = xyz, then tan^-1x + tan^-1y + tan^-1z =

π/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

tan-1 (xyz)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
π

Suggest Corrections

Similar questions

{tan}^{- 1} x + {tan}^{- 1} y + {tan}^{- 1} z = π

x + y + z = x y z

x + y + z = x y z

x, y, z > 0

{tan}^{- 1} x + {tan}^{- 1} y + {tan}^{- 1} z

If $t a n^{- 1} x + t a n^{- 1} y + t a n^{- 1} z = π,$ then $x + y + z$ is equal to
[Kerala (Engg.) 2002]

$I f t a n^{- 1} x + t a n^{- 1} y + t a n^{- 1} z = \frac{π}{2}, t h e n x y + y z + z x =$

x, y, z

A . P

{tan}^{- 1} x, {tan}^{- 1} y

{tan}^{- 1} z

A . P

Join BYJU'S Learning Program