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Absolute Value Function

If x 2+1 × 2=...

Question

If $x^{2} + \frac{1}{x^{2}} = 66$ , find the value of $x - \frac{1}{x}$

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Solution

In the given problem, we have to find

Given

Adding and subtracting 2 on left hand side

Hence the value of is

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Similar questions

If $x^{2} + \frac{1}{x^{2}} = 66,$ find the value of $x - \frac{1}{x}$ .

x^{2} + \frac{1}{x^{2}} = 18,

find the values of

x + \frac{1}{x} and x - \frac{1}{x} .

x^{2} + \frac{1}{x^{2}} = 66

,find the value of

x

\frac{1}{\sqrt{2}} < x < 1

, then find the value of

{cos}^{- 1} x + {cos}^{- 1} (\frac{x + \sqrt{1 - x^{2}}}{\sqrt{2}})

.

x = 3 - 2 \sqrt{2}

, find the value of:
i)

\frac{1}{x}

x + \frac{1}{x}

x - \frac{1}{x}

\sqrt{x} + \frac{1}{\sqrt{x}}

\sqrt{x} - \frac{1}{\sqrt{x}}

x^{2} + \frac{1}{x^{2}}

x^{2} - \frac{1}{x^{2}}

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