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Roots of a Quadratic Equation

If x2 + 4x – ...

Question

If (x² + 4x – 2)² = (5x² – 1)², then the number of distinct real solutions of x which satisfy the given equation is

यदि (x² + 4x – 2)² = (5x² – 1)², तब दी गयी समीकरण को संतुष्ट करने वाले x के भिन्न वास्तविक हलों की संख्या है

A

4

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B

2

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C

1

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D

3

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Solution

The correct option is D 3
Solution

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Q. More than One Answer Type
एक से अधिक उत्तर प्रकार के प्रश्न

If the number of integral solutions (non-positive) satisfying x + y + z + w = –10 are λ, then λ is less than

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