If x3-y3-3x2y-3xy2-27- then dydx-1

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Implicit Differentiation

If x3+y3+3x2y...

Question

If $x^{3} + y^{3} + 3 x^{2} y + 3 x y^{2} = 27,$
then $\frac{d y}{d x} = - 1$

True

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False

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Solution

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Similar questions

The expansion of ${(x + y)}^{3}$ is

The expansion of ${(x + y)}^{3}$ is $x^{3} + y^{3} + 3 x^{2} y - 3 x y^{2}$

\frac{a^{3} + 3 a b^{2}}{3 a^{2} b + b^{3}} = \frac{x^{3} + 3 x y^{2}}{3 x^{2} y + y^{3}}

x^{3} - y^{3} + 3 x y^{2} - 3 x^{2} y + 1 = 0

(0, 1)

\frac{d y}{d x}

x^{3} + 3 x^{2} y + 3 x y^{2} + y^{3} - 8

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