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Question

If xeyy=sinx, then the value of dydx at x=0 is

[1 mark]

A
1
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B
1
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C
2
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D
0
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Solution

The correct option is D 0
We have,
xeyy=sinx (1)
Differentiating both sides with respect to x, we get
ey+xeydydxdydx=cosx
dydx(xey1)=cosxey
dydx=cosxeyxey1
At x=0,y=0 [From (1)]
dydx(0,0)=111=0

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