ξ= { 1,2,3,4,5,6,7,8,9,10 } as x is a natural number less than or equal to 10.
A= { 4,5,6,7,8,9,10 } as x is a number greater
than or equal to 4 and the universal set is already defined as ξ.
And, B= { 3,4,5,6 } as x is a natural number less than 7 and more than 2.
Intersection of two sets has the elements common in both the sets.
So, A∩B= { 4,5,6 }.
And
(A∩B)′=ξ−(A∩B)= {1,2,3,7,8,9,10 } (Since, ξ−(A∩B) will have the elements of ξ which are not in (A∩B ).