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Question

If xy>0, which of the following has to be true?
I. x+y=0
II. 2y−2x<0
III. x2+y2>0

A
I only
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B
III only
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C
I and III
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D
II and III
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Solution

The correct option is B III only
Given, xy>0x>0 and y>0 or x<0 and y<0
Adding both x>0 and y>0, we get
x+y>0 or x+y<0
I. Hence, x+y=0 is false

Subtracting x from y we get,
yx>0 or yx=0 or yx<0
II. Hence, 2y2x<0 is not always true.

Squaring both, we get x2>0 and y2>0
Adding both x2>0 and y2>0
we get x2+y2>0
III. Hence, x2+y2>0 is true

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