If xy=6 and x+x^2y+xy^2+y = 63, then x^2+y^2 =
x^2y + y^2x + x +y=63
xy(x+y)+x+y=63(taking xy common)
6(x+y)+x+y=63 (xy= 6 ,given)
6x+6y+x+y=63
7x+7y=63
x+y=9
(x+y)2= x^2+2xy+y^2
(9)^2=x2+2(6)+y2
81= x^2+12+y^2
x^2+y^2=81-12
=69
Question 6 If two positive integers a and b are written as a=x3y2 and b=xy2 where x, y are prime numbers, then HCF (a, b) is A) xy B) xy2 C) x3y3 D) x2y2